Answer
$Zinc = 3.3\times10^{24}atoms\\
Copper = 5.7\times10^{24} atoms$
Work Step by Step
1. Total mass = Density x volume
$8.48\times112.5=954\ g$
2. Multiply total mass by percent to find how much zinc weighs and how much copper weighs.
$0.37\times954=352.98g\ Zn$
$(.100-.37)\times954=601.02g\ Cu$
3. find the moles of each compound
$601.02/63.55= 9.46\ Mol\ of\ Cu$
4. Multiply moles by $6.022\times10^{23}$ for the amount of atoms = $5.7\times10^{24} atoms\ of\ Cu$
5. Do the same for zinc, $352.98/65 38 =5.4 Mol$
$5.4\times 6.022\times10^{23}=3.3\times10^{24}atoms\ of\ Zn$
