Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Cumulative Problems - Page 83: 113

Answer

$4.76\times10^{24}\,atoms$

Work Step by Step

$Radius=0.935\,in\times\frac{2.54\,cm}{1\,in}=2.3749\, cm$ $Volume=\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi\times(2.3749\, cm)^{3}=56.1\,cm^{3}$ $Mass= Density\times Volume= 8.96g/cm^{3}\times56.1\,cm^{3} =502.656\,g$ Number of moles of Cu=$\frac{Mass\,in\,grams}{Molar\,mass}=\frac{502.656\,g}{63.546\,g/mol}=7.91\,mol$ Number of atoms of Cu=$7.91\,mol\times\frac{6.022\times10^{23}}{1\,mol}=4.76\times10^{24}\,atoms$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.