Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 2 - Sections 2.1-2.9 - Exercises - Cumulative Problems - Page 83: 110

Answer

$2.3\times10^{17}\ automobiles$

Work Step by Step

1. Compute the mass of 1.0 mol of blueberries using conversion factors. $1\ mol \ blueberry\times\frac{6.022\times10^{23}\ blueberry}{1\ mol \ blueberry}\times\frac{0.75\ g}{1\ blueberry}= 4.5165\times10^{23}\ g$ 2. Divide the mass of these blueberries by the mass of an automobile in order to determine how many automobiles are needed to equal the mass of the blueberries. $n= \frac{4.5165\times10^{23}\ g}{2\times10^{3}\times10^3\ g}= 2.3\times10^{17}\ automobiles$
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