Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 15 - Sections 15.1-15.12 - Exercises - Problems by Topic - Page 746: 40

Answer

$HCO_{3}^{-}(aq) + HS^-(aq) \rightleftharpoons CO_{3}^{2-}(aq) + H_{2}S(aq)$ Here, $HCO_{3}^{-}(aq)$ is the acid and $HS^-(aq)$ is the base. $HCO_{3}^{-}(aq) + HS^-(aq) \rightleftharpoons H_{2}CO_{3}(aq) + S^{2-}(aq)$ Here, $HCO_{3}^{-}(aq)$ is the base and $HS^-(aq)$ is the acid.

Work Step by Step

According to the definition, Acid: proton ($H^{+}$ ion) donor Base: proton ($H^{+}$ ion) acceptor In the first reaction, $HCO_{3}^{-}$ is an acid because it donates a proton. $HS^-$ is a base because it accepts the proton. In the second reaction, $HS^-$ is an acid because it donates a proton. $HCO_{3}^{-}$ is a base because it accepts the proton.
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