Answer
Mole fraction = 0.00794
Work Step by Step
1. Calculate the molar mass for each compound (glucose and water):
Molar Mass ($C_6H_{12}O_6$):
$C: 12.01g * 6= 72.06g $
$H: 1.008g * 12= 12.10g $
$O: 16.00g * 6= 96.00g $
$72.06g/mol + 12.10g/mol + 96.00g/mol = 180.16g/mol$
Molar Mass ($H_2O$):
$H: 1.008g * 2= 2.016g $
$O: 16.00g$
$2.016g/mol + 16.00g/mol = 18.02g/mol$
- The formula for mole fraction is:
$\frac{n_{solute}}{n_{solute} + n_{solvent}} $
** Notice: $n = \frac{mass}{mm}$
$\frac{\frac{28.4g}{180.16g/mol}}{\frac{28.4g}{180.16g/mol} + \frac{355g}{18.02g/mol}} = 0.00794$
