Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 12 - Sections 12.1-12.8 - Exercises - Problems by Topic - Page 590: 63a

Answer

0.417 M

Work Step by Step

Molarity=$ \frac{Number\,of\,moles\,of\,solute}{Volume\, of\, solution\,in\,L}=\frac{\frac{Mass\,of\,glucose}{Molar\,mass}}{Volume\,of\, solution\,in\,L}$ $=\frac{\frac{28.4g}{180.\,g/mol}}{0.378L}=0.417\,M$
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