Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 12 - Sections 12.1-12.8 - Exercises - Problems by Topic - Page 590: 63c

Answer

The glucose concentration is equal to 7.41 % by mass

Work Step by Step

- The percent by mass formula is: $\% by \space mass = \frac{mass_{solute}}{mass_{solute} + mass_{solvent}} \times 100\%$ $= \frac{mass_{glucose}}{mass_{glucose} + mass_{water}} \times 100\%$ $= \frac{28.4 \space g}{28.4 \space g + 355 \space g } \times 100\% = 7.41 \% \space by \space mass$
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