Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Challenge Problems - Page 42: 138d

Answer

$$1.28 \times 10^{20} \space nanocontainers$$

Work Step by Step

As we have calculated in 138b and 138c: - Each nanocontainer contains $1.328125 \times 10^{-18} \space g$ of oxygen. - A human inhale 170 g of Oxygen per hour. Therefore, 1 hour's worth of oxygen = 170 g $O_2$ - Calculate the number of nanocontainers: $$170 \space g \space O_2 \times \frac{1 \space nanocontainer}{1.328125 \times 10^{18} \space g \space O_2} = 1.28 \times 10^{20} \space nanocontainers$$
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