Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Challenge Problems - Page 42: 138b


$1.328125\times 10^{-18}g$

Work Step by Step

We know that $\rho=\frac{m}{V}$ Where $\rho$, $m$ and $V$ are density, mass and volume of oxygen respectively The above equation can be rearranged as $m =V\times \rho$ We plug in the known values to obtain: $m=1.5625\times 10^{-20}\times 85=1.328125\times 10^{-18}g$
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