Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 1 - Sections 1.1-1.8 - Exercises - Challenge Problems - Page 42: 133


18.2 atm

Work Step by Step

Firstly, we convert cm$^{2}$ to m$^{2}$ 1 cm$^{2}$ = 1$\times10^{-4}$ m$^{2}$ 125cm$^{2}$ = 0.0125m$^{2}$ Secondly, We find the pressure in Pascals using the following equation: Pressure=$\frac{Force}{Area}$ Pressure=$\frac{2.31\times10^{4}N}{0.0125m^{2}}$ = 1848000 Pa In the last step we convert Pascal into atm 1 atm= 101325 Pa $\frac{1848000}{101325}$ = 18.2 atm
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