Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 237: 78



Work Step by Step

$\text{ Molar Mass}=\frac{\frac{0.800}{0.256}*0.08206*373}{\frac{750}{760}}=96.9\text{ g/mol}$ $\text{ Molar Mass of } CHCl=48.4689$ $\frac{96.9}{48.4689}=2$ Therefore, the molecular formula is $C_2H_2Cl_2$
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