## Chemistry 9th Edition

$Cl_{2(g)}$
$\text{ Molar Mass}=\frac{dRT}{P}$ $\text{ Molar Mass}=\frac{3.164*0.08206*273}{1.00}$ $\text{ Molar Mass}=70.9$ Molar mass of $Cl_2$ = 70.9 Therefore, the diatomic gas is likely $Cl_2$