Answer
$Cl_{2(g)}$
Work Step by Step
$\text{ Molar Mass}=\frac{dRT}{P}$
$\text{ Molar Mass}=\frac{3.164*0.08206*273}{1.00}$
$\text{ Molar Mass}=70.9$
Molar mass of $Cl_2$ = 70.9
Therefore, the diatomic gas is likely $Cl_2$
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