Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises - Page 237: 77



Work Step by Step

$\text{ Molar Mass}=\frac{dRT}{P}$ $\text{ Molar Mass}=\frac{3.164*0.08206*273}{1.00}$ $\text{ Molar Mass}=70.9$ Molar mass of $Cl_2$ = 70.9 Therefore, the diatomic gas is likely $Cl_2$
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