Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 5 - Gases - Exercises: 66

Answer

$2.04\text{ L $CO_2$}$

Work Step by Step

$4.00\text{ grams $CO_2$}*\frac{1\text{ mol $CO_2$}}{44.01\text{ grams $CO_2$}}*\frac{22.42 \text{ L}}{1\text{ mol $CO_2$}}=2.04\text{ L $CO_2$}$
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