Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 85

Answer

Compound 1: $HgO$ Compound 2: $Hg_2O$

Work Step by Step

Compound 1: $\frac{0.6018}{0.6498}=92.6\text{ percent Mercury and $7.4$ percent Oxygen}$ $92.6\text{ grams Hg}*\frac{1\text{ mol Hg}}{200.59\text{ grams Hg}}=0.462\text{ mol Hg}$ $7.4\text{ grams O}*\frac{1\text{ mol O}}{15.9994\text{ grams O}}=0.465\text{ mol O}$ $0.462:0.465=1:1\Rightarrow HgO$ Compound 2: $\frac{0.016}{0.4172}=3.835\text{ percent O and $96.165$ percent Hg}$ $96.165\text{ grams Hg}*\frac{1\text{ mol Hg}}{200.59\text{ grams Hg}}=0.479\text{ mol Hg}$ $3.825\text{ grams O}*\frac{1\text{ mol O}}{15.9994\text{ grams O}}=0.2397\text{ mol O}$ $0.479:0.2397\Rightarrow 2:1 \Rightarrow Hg_2O$
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