## Chemistry 9th Edition

$C_3H_6O_2$
We assume we have $100$ grams of the compound. Therefore, we have 48.64 grams of C, 8.16 grams of H, and 43.2 grams of O. $48.64\text{ grams C}*\frac{1\text{ mol C}}{12.0107\text{ grams C}}=4.0497\text{ mol C}$ $8.16\text{ grams H}*\frac{1\text{ mol H}}{1.00794\text{ grams H}}=8.0957\text{ mol H}$ $43.2\text{ grams O}*\frac{1\text{ mol O}}{15.9994\text{ grams O}}=2.7\text{ mol O}$ $4.05:8.0957:2.7=3:6:2$ $C_3H_6O_2$