Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 130: 83



Work Step by Step

We assume we have $100$ grams of the compound. Therefore, we have 48.64 grams of C, 8.16 grams of H, and 43.2 grams of O. $48.64\text{ grams C}*\frac{1\text{ mol C}}{12.0107\text{ grams C}}=4.0497\text{ mol C}$ $8.16\text{ grams H}*\frac{1\text{ mol H}}{1.00794\text{ grams H}}=8.0957\text{ mol H}$ $43.2\text{ grams O}*\frac{1\text{ mol O}}{15.9994\text{ grams O}}=2.7\text{ mol O}$ $4.05:8.0957:2.7=3:6:2$ $C_3H_6O_2$
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