# Chapter 3 - Stoichiometry - Exercises - Page 130: 75

The formula is $NO$ which corresponds the compound with one $N$ atom and one $O$ atom.

#### Work Step by Step

Assume, we have 100 grams of the compound. Therefore, we have 46.7 grams of N and 53.3 grams of O. $46.7\text{ grams N}*\frac{1\text{ mol N}}{14.0067\text{ grams N}}=3.33\text{ mol N}$ $53.3\text{ grams O}*\frac{1\text{ mol O}}{15.9994\text{ grams O}}=3.33\text{ mol O}$ $3.33\text{ mol N}:3.33\text{ mol O}=1\text{ mol N}:1\text{ mol O}$ Therefore the formula is $NO$ which corresponds the compound with one $N$ atom and one $O$ atom.

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