Answer
67.9 kJ
Work Step by Step
We find:
$q=mc\Delta T=250.0\,g\times\frac{4.18\,J}{g\cdot \,^{\circ}C}\times(90.0-25.0)^{\circ}C$
$=67900\,J=67.9\,kJ$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 9 - Thermochemistry: Chemical Energy - Section Problems - Page 352: 77
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