Answer
-32 kJ
Work Step by Step
We find:
$q=mc\Delta T=350\,g\times\frac{4.18\,J}{g\cdot \,^{\circ}C}\times(3-25)^{\circ}C$
$=-32000\,J=-32\,kJ$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 9 - Thermochemistry: Chemical Energy - Section Problems - Page 352: 76
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
