## Chemistry (7th Edition)

(a) Hydrofluoric acid $(HF)$ is a weak electrolyte (according to the table 4.1, Page 118); therefore, the light bulb will only receive part of the electricity. (a) Sodium chloride ($NaCl$) is an ionic compound, which is very dissociated in water. Therefore, the solution will be very conductive. (b) Glucose is a very molecular compound, which makes it a bad conductor in water.