Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 4 - Reactions in Aqueous Solution - Section Problems - Page 148: 50

Answer

160 mL=.16 L

Work Step by Step

Mass of $BaCl_{2}$ = 15.0 g Molar mass of $BaCl_{2}$ = 208.23 g/mol Molarity = 0.45 M = 0.45 mol/L Volume of solution in L = $\frac{Mass\div Molar.mass}{Molarity}$ = $\frac{15.0g\div208.23gmol^{-1}}{0.45molL^{-1}}$ = 0.16 L = 160 mL
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