## Chemistry (7th Edition)

Mass of $BaCl_{2}$ = 15.0 g Molar mass of $BaCl_{2}$ = 208.23 g/mol Molarity = 0.45 M = 0.45 mol/L Volume of solution in L = $\frac{Mass\div Molar.mass}{Molarity}$ = $\frac{15.0g\div208.23gmol^{-1}}{0.45molL^{-1}}$ = 0.16 L = 160 mL