## Chemistry (7th Edition)

(a) 15.0g (b) 4 tablets (c) $5.18 \times 10^{22}$ molecules.
(a) As we can see in the previous worked examples, the molar mass for glucose is equal to 180.0 g/mol. $0.0833 mol \times \frac{180.0g}{1mol} = 15.0$ g. (b) $15.0$ g $\times \frac{1 tablet}{3.75g } = 4$ $tablets$. (c) $0.0833 mol \times \frac{6.022 \times 10^{23} molecules}{1 mol} = 5.18 \times 10^{22}$ molecules.