## Chemistry (7th Edition)

There are 0.0626 mol of $NaHCO_3$ in Alka-Seltzer tablets.
1. Calculate the molar mass $(NaHCO_3)$: 22.99* 1 + 1.008* 1 + 12.01* 1 + 16.00* 3 = 84.01g/mol 2. Calculate the number of moles $(NaHCO_3)$ $n(moles) = \frac{mass(g)}{mm(g/mol)}$ $n(moles) = \frac{ 5.26}{ 84.01}$ $n(moles) = 0.0626$ Or, you can use other method: $5.26 g \times \frac{1 mol}{84.01g} = 0.0626 mol$