Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 19 - Nuclear Chemistry - Section Problems - Page 836: 34

Answer

alpha

Work Step by Step

Let the particle be $\,^{A}_{Z}X$ We can write the nuclear equation as: $^{214}_{90}Th\rightarrow \,\,^{210}_{88}Ra+\,^{A}_{Z}X$ Sum of charges and masses should be equal on both sides. This implies that $214=210+A$ or $A=4$ and $90=88+Z$ or $Z=2$ The particle with mass 4 and charge 2 is produced. The particle is alpha.
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