Chapter 15 - Aqueous Equilibria: Acids and Bases - Worked Example - Page 618: 14

The concentration of hydronium in coffee is about 39.81 times greater than in milk.

Work Step by Step

- Milk: $[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 6.6}$ $[H_3O^+] = 2.512 \times 10^{- 7}M$ - Black coffe: $[H_3O^+] = 10^{-pH}$ $[H_3O^+] = 10^{- 5}M$ $[H_3O^+] = 1 \times 10^{- 5}$ - Divide the coffee hydronium concentration by the milk's. $\frac{ 1 \times 10^{-5}}{2.512 \times 10^{-7}} \approx 39.81$ times.

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