Chemistry (7th Edition)

Published by Pearson
ISBN 10: 0321943171
ISBN 13: 978-0-32194-317-0

Chapter 1 - Chemical Tools: Experimentation and Measurement - Worked Example - Page 7: 2

Answer

(a) $7.0 \times 10^{-5}$ m; (b) $2.0 \times 10^{10}$ kg;

Work Step by Step

(a) As we can see in the previous table: $μ$ = $10^{-6}$; therefore: $70$ $μm$ = $70 \times 10^{-6}$ $m$ = $7.0 \times 10^{-5}$ $m$ (b) T equals $10^{12}$; therefore: $20$ $Tg$ $=$ $20 \times 10^{12}$ $g$ = $2.0 \times 10^{13}$ $g$ But, the SI unit for mass is actually kg, and $kg= 10^3 g$; therefore: $2.0 \times 10^{13}$ $g = 2.0 \times \frac{10^{13}}{10^3} kg = 2.0 \times 10^{10}$ $kg$.
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