Answer
$1474$ $^{\circ}F$ is equal to $801$ $^{\circ}C$ and $1074$ $K$.
Work Step by Step
We find
$^{\circ}C = (\frac{5^{\circ}C }{9^{\circ}F})(1474^{\circ}F-32^{\circ}F) = 801$ $^{\circ}C$
$K = ^{\circ}C + 273.15 = 801 + 273.15 = 1074$ $K$
Chemistry (7th Edition)
by McMurry, John E.; Fay, Robert C.; Robinson, Jill Kirsten
Published by
Pearson
ISBN 10:
0321943171
ISBN 13:
978-0-32194-317-0
Chapter 1 - Chemical Tools: Experimentation and Measurement - Worked Example - Page 11: 3
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