## Chemistry (7th Edition)

Published by Pearson

# Chapter 1 - Chemical Tools: Experimentation and Measurement - Section Problems - Page 31: 86

#### Answer

$11 g/cm^{3}$

#### Work Step by Step

Volume = $0.50 cm\times1.55 cm\times25.00cm$ Mass = 220.9 g Density = $\frac{Mass}{Volume} = \frac{220.9g}{0.50 cm\times1.55 cm\times25.00cm} = \frac{220.9 g}{19.375cm^{3}} = 11 \frac{g}{cm^{3}}$ (rounded at the end to 2 significant figures as 0.50 contains only 2 significant figures).

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