## Chemistry (7th Edition)

Published by Pearson

# Chapter 1 - Chemical Tools: Experimentation and Measurement - Section Problems - Page 31: 85

#### Answer

The mass of this cube of silver is equal to $2.5 \times 10^3kg$

#### Work Step by Step

1. Calculate the cube's volume: $0.62$ $m \times \frac{1cm}{10^{-2}m} = 62$ $cm$ $Volume (cube) = (side lenght)^3 = (62cm)^3 = 2.4 \times 10^5cm^3$ 2. Now, find the mass of this silver cube: $2.4 \times 10^5 cm^3 \times \frac{10.5g}{1cm^3} = 2.5 \times 10^6g$ $2.5 \times 10^6g \times \frac{1kg}{10^{3}g} = 2.5 \times 10^3kg$

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