Answer
(c) 0.057 is the correct answer.
Work Step by Step
1. Convert the lenght and dipole moment to "C.m"and "m".
$$\mu = 0.44 \ D\times \frac{3.336 \times 10^{-30} C.m}{1 \ D} = 1.47 \times 10^{-30} C.m$$
$$r = 1.61 Å \times \frac{1 \times 10^{-10} m}{1 \ Å} = 1.61 \times 10^{-10} m$$
2. Using Equation 8.1:
$$Q = \frac{\mu}{r} = \frac{ 1.47 \times 10^{-30} C.m}{1.61 \times 10^{-10} m} = 9.13 \times 10^{-21} C$$
3. Convert to units of electronic charge:
$$Q = 9.13 \times 10^{-21} C \times \frac{ 1 e^-}{1.6022 \times 10^{-19} C} = 0.057 e^-$$
