Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 8 - Section 8.4 - Electronegativity and Polarity - Checkpoint - Page 342: 8.4.1

Answer

(b) $H_2O$ has the most polar bonds.

Work Step by Step

We can use Figure 8.9 to calculate the difference between the electronegativity of each pair of atoms. (a) 2.4 - 2.1 = 0.3 (b) 3.5 - 2.1 = 1.4 (c) 3.5 - 2.5 = 1.0 (d) 3.0 - 2.0 = 1.0 (e) 3.0 - 2.1 = 0.9 The one with greater difference of electronegativity is (b) $H_2O$. Therefore it has the most polar bonds.
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