Answer
The orbitals which have higher energy than $3s$ are $4s$ and $4p$.
Work Step by Step
The energy of an orbital of hydrogen or any one-electron system depends only on the principal quantum number $n$ and increases with $n$.
$3s$ orbital corresponds to the principal quantum number $n=3$.
Hence, the orbitals which have higher energy than $3s$ are $4s$ and $4p$.
