Answer
$\therefore \text{Number of oribtals in subshell 5f}=7 $
Work Step by Step
$\textbf{Note: }$Number of orbitals in a subshell ( $l$ ) is $2l+1$.
$5f$ corresponds to subshell $l=3$
$\therefore \text{Number of oribtals }=2\times 3+1=7 $
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 6 - Section 6.7 - Atomic Orbitals - Checkpoint - Page 262: 6.7.1
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