Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 6 - Section 6.3 - Bohr’s Theory of the Hydrogen Atom - Checkpoint: 6.3.1

Answer

b) -2.42$\times10^{-19} J$

Work Step by Step

Using equation $E_{n} = -R_{H}(\frac{1}{n^{2}})$ , We get $E_{3} = -2.18\times10^{-18}(\frac{1}{9}) = -2.42\times10^{-19} J$.
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