Answer
(d) $2.09\times10^{-18}\,J$
Work Step by Step
$n_{i}=1$ and $n_{f}=5$
$\Delta E=-2.18\times10^{-18}\,J(\frac{1}{n_{f}^{2}}-\frac{1}{n_{i}^{2}})$
$=-2.18\times10^{-18}\,J(\frac{1}{5^{2}}-\frac{1}{1^{2}})$
$=2.09\times10^{-18}\,J$
Chemistry (4th Edition)
by Burdge, Julia
Published by
McGraw-Hill Publishing Company
ISBN 10:
0078021529
ISBN 13:
978-0-07802-152-7
Chapter 6 - Section 6.3 - Bohr’s Theory of the Hydrogen Atom - Checkpoint - Page 250: 6.3.2
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