Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 6 - Section 6.2 - Quantum Theory - Checkpoint: 6.2.2

Answer

d) 1.51 cm.

Work Step by Step

λ=$\frac{hc}{E}$ , where h is the Planck's constant, c is the speed of light and E the energy of one photon. i.e. λ= $\frac{6.626\times10^{-34}Js\times3.00\times10^{8}ms^{-1}}{1.32\times10^{-23}J}$ = 1.51 cm.
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