Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 6 - Section 6.2 - Quantum Theory - Checkpoint: 6.2.1

Answer

e) 3.06$\times10^{-19}$ J

Work Step by Step

E = h$\frac{c}{λ} = \frac{6.626\times10^{-34}J s\times3.00\times10^{8}ms^{-1}}{650\times10^{-9}m}$ = 3.06$\times10^{-19}$ J
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