# Chapter 5 - Questions and Problems - Page 221: 5.28

15700 kJ

#### Work Step by Step

Moles of $NO_{2}=\frac{mass\,in\,grams}{molar\,mass\,of\,NO_{2}}$ $=\frac{1.26\times10^{4}\,g}{46.0\,g/mol}=274\,mol$ When 2 moles of $NO_{2}$ are produced, heat given off is 114.6 kJ. This implies that the heat given off per mole $NO_{2}$ produced is 57.3 kJ. Heat given off when 274 mol of $NO_{2}$ are produced= $274\,mol\times57.3\,kJ/mol=15700\,kJ$

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