## Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company

# Chapter 5 - Questions and Problems - Page 221: 5.15

#### Answer

w = 925 J , work is done on the system.

#### Work Step by Step

Given, $\Delta U$= 510 J; q = -415 J ( negative sign for exothermic process). We know, $\Delta U$ = q+w or w= $\Delta U$-q = 510 J-(-415 J)= 925 J. Sign is positive which indicates that the work is done on the system.

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