Answer
w = 925 J , work is done on the system.
Work Step by Step
Given, $\Delta U$= 510 J;
q = -415 J ( negative sign for exothermic process).
We know, $\Delta U$ = q+w or w= $\Delta U$-q = 510 J-(-415 J)= 925 J.
Sign is positive which indicates that the work is done on the system.
