We should add 126 mL of water.
Work Step by Step
1. Find the necessary volume: $C_1 * V_1 = C_2 * V_2$ $ 0.125* 505= 0.100 * V_2$ $ 63.125 = 0.100 * V_2$ $V_2 = 631$ mL 2. Calculate the volume difference: 631 mL - 505 mL = 126 mL
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