Chapter 4 - Questions and Problems - Page 179: 4.67

First, add 323 mL of the $2.00$ M $HCl$ solution to an adequate recipient, and then add water until the solution reaches a volume of 1.00 L.

1. Find the necessary volume for the dilution: $C_1 * V_1 = C_2 * V_2$ $ 0.646* 1.00= 2.00 * V_2$ $ 0.646 = 2.00 * V_2$ $V_2 = 0.323$ L 2. Convert that number to mL: 1 L = 1000 mL $0.323$ L = 0.323 $\times$ 1000 mL = 323 mL