Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 3 - Questions and Problems - Page 120: 3.46


6.69$\times10^{21}$ molecules.

Work Step by Step

Mass in grams = 0.334g Molar mass = 2 (12.011g) + 6(1.008g) Number of moles = mass in grams/molar mass. Number of molecules = No of moles$\times N_{A}$ No of molecules= $\frac{0.334g}{30.07gmol^{-1}}\times 6.022\times10^{23}\approx6.69\times10^{21}$
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