Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 3 - Questions and Problems - Page 120: 3.32


It would take $1.4 \times 10^9$ years to count that many particles.

Work Step by Step

$6.0 \times 10^{23}$ particles $\times \frac{1 second}{2 particles} = 3.0 \times 10^{23} seconds$ We are going to divide that work by 7 billion people ($7.0 \times 10^9$) $\frac{3.0 \times 10^{23}seconds}{7.0\times10^9} = 4.3 \times 10^{13} seconds.$ $4.3 \times 10^{13} seconds \times \frac{1 hour}{3600 seconds} \times \frac{1 day}{24 hour} \times \frac{1 year}{365 days} = 1.4 \times 10^9$ years.
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