## Chemistry (4th Edition)

The $Ba(OH)_2$ concentration is equal to $0.47M$
1000ml = 1L 20.4ml = 0.0204 L 19.3ml = 0.0193 L 1. Find the volume necessary for an equal number of moles: ** Since $Ba(OH)_2$ has 2 $OH^-$ in it, we must multiply its concentration by 2. $C_1 * V_1 = V_2 * C_2$ $0.883* 0.0204= 0.0193 * (2 * C_2)$ $0.0180 = 0.0193 * (2 * C_2)$ $2 * C_2 = 0.933$ $C_2 = 0.467$