# Chapter 17 - Questions and Problems - Page 825: 17.29

The concentration of $NaOH$ is $0.25M$

#### Work Step by Step

1. Find the concentration necessary for an equal number of moles: 12.5ml = 0.0125L 50.0ml = 0.050L ** Since $H_2SO_4$ is a diprotic acid, we have to multiply its concentration by 2 (to get the Hydronium ion concentration in it). $C_1 * V_1 = V_2 * C_2$ $(0.500*2)* 0.0125= 0.050 * C_2$ $0.0125 = 0.050 * C_2$ $C_2 = 0.25M$

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