Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 16 - Questions and Problems - Page 770: 16.6


(a) $H_2S$ (b) $H_2CO_3$ (c) $HC{O_3}^-$ (d) $H_3PO_4$ (e) $H_2P{O_4}^-$ (f) $HP{O_4}^{2-}$ (g) $H_2SO_4$ (h) $HS{O_4}^-$ (i) $HS{O_3}^-$

Work Step by Step

A conjugate acid is the result of a base, after receiving one proton, therefore, all we need to do is: 1. Add a "H" to the formula: Ex: $HS^-$ -> $H_2S^-$ 2. Add +1 to the molecule charge: * (-1) + 1 = 0 Ex: $H_2S^-$ -> $H_2S$
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