Chemistry (4th Edition)

(a) $H_2S$ (b) $H_2CO_3$ (c) $HC{O_3}^-$ (d) $H_3PO_4$ (e) $H_2P{O_4}^-$ (f) $HP{O_4}^{2-}$ (g) $H_2SO_4$ (h) $HS{O_4}^-$ (i) $HS{O_3}^-$
A conjugate acid is the result of a base, after receiving one proton, therefore, all we need to do is: 1. Add a "H" to the formula: Ex: $HS^-$ -> $H_2S^-$ 2. Add +1 to the molecule charge: * (-1) + 1 = 0 Ex: $H_2S^-$ -> $H_2S$