Answer
(a) $H_2S$
(b) $H_2CO_3$
(c) $HC{O_3}^-$
(d) $H_3PO_4$
(e) $H_2P{O_4}^-$
(f) $HP{O_4}^{2-}$
(g) $H_2SO_4$
(h) $HS{O_4}^-$
(i) $HS{O_3}^-$
Work Step by Step
A conjugate acid is the result of a base, after receiving one proton, therefore, all we need to do is:
1. Add a "H" to the formula:
Ex: $HS^-$ -> $H_2S^-$
2. Add +1 to the molecule charge:
* (-1) + 1 = 0
Ex: $H_2S^-$ -> $H_2S$
