Answer
(a)
- $CH_3COO^-$ : Base, $CH_3COOH$ : Acid
- $HCN$: Acid, $CN^-$ : Base
(b)
- $HC{O_3}^-$ : Base, $H_2CO_3$ : Acid
- $HC{O_3}^-$ : Acid, $C{O_3}^{2-}$ : Base
(c)
- $H_2P{O_4}^-$ : Acid, $HP{O_4}^{2-}$: Base
- $NH_3$: Base, $N{H_4}^+$: Acid
(d)
- $HClO$: Acid, $ClO^-$: Base
- $CH_3NH_2$: Base, $CH_3N{H_3}^+$: Acid
(e)
- $C{O_3}^{2-}$: Base, $HC{O_3}^-$: Acid
- $H_2O$: Acid, $OH^-$: Base
Work Step by Step
To identify a conjugate acid-base pair:
1. Identify the acid on the right.
2. The conjugate base of this acid will be this acids without a 4 $H^+$, so search it on the other side of the reaction.
3. Do 1 and 2 for the base on the right, but looking for the base with a $H^+$ in it, you will find its conjugate acid.
