Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 15 - Section 15.3 - Equilibrium Expressions - Checkpoint - Page 678: 15.3.2


a)$$K_c = \frac{1}{[CO_2]}$$

Work Step by Step

1. Write the expression including all compounds of the reaction: $$K_c = \frac{[CaCO_3]}{[CaO][CO_2]}$$ 2. But, since $CaO$ and $CaCO_3$ appear in the solid state, their concentrations are approximately constant, so they will not appear in the Kc expression: $$K_c = \frac{1}{[CO_2]}$$
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