Chemistry (4th Edition)

Published by McGraw-Hill Publishing Company
ISBN 10: 0078021529
ISBN 13: 978-0-07802-152-7

Chapter 15 - Section 15.3 - Equilibrium Expressions - Checkpoint - Page 678: 15.3.1


d)$$K_c = \frac{1}{[H^+][OH^-]}$$

Work Step by Step

1. Write the expression including all compounds of the reaction: $$K_c = \frac{[H_2O]}{[H^+][OH^-]}$$ 2. But, since $H_2O$ appears in the liquid state, its concentration is approximately constant, so it will not appear in the Kc expression: $$K_c = \frac{1}{[H^+][OH^-]}$$
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