Answer
(a) 1.7 atm$^{-1}$
(b)
$P_A$ = 0.69 atm.
$P_ B$ = 0.81 atm
Work Step by Step
(a) $$K_p = \frac{P_B}{P_A^2} = \frac{0.60 atm}{0.60^2 atm^2} = 1.7 atm^{-1}$$
(b) $P_A + P_B = 1.5 -> P_B = 1.5 - P_A$
$$1.7= \frac{1.5 - P_A}{P_A^2} $$
$$1.7 P_A^2 + P_A - 1.5 = 0$$
Solving using bhaskara:
$$P_{A1} = -1.23 $$
$$P_{A2} = 0.69$$
Pressures cannot be negative, so $P_A$ = 0.69 atm.
$P_ B = 1.5 - 0.69 = 0.81 atm$
