## Chemistry (4th Edition)

$P_{ COCl_2 } = 0.703 \space atm$ $P_{ CO }=0.0570 \space atm$ $P_{ Cl_2 }= 0.0570 \space atm$
1. Write the equilibrium constant expression: - The exponent of each concentration is equal to its balance coefficient. $$K_c = \frac{[Products]}{[Reactants]} = \frac{P_{ CO }P_{ Cl_2 }}{P_{ COCl_2 }}$$ 2. At equilibrium, these are the concentrations of each compound: $P_{ COCl_2 } = 0.760 \space M - x$ $P_{ CO } = 0 \space M + x$ $P_{ Cl_2 } = 0 \space M + x$ $$4.63 \times 10^{-3} = \frac{(x)(x)}{(0.760 - x)}$$ x = 0.0570 $P_{ COCl_2 } = 0.760 \space M - 0.0570 M = 0.703 atm$ $P_{ CO } = 0 \space M + 0.0570 M = 0.0570 atm$ $P_{ Cl_2 } = 0 \space M + 0.0570 M = 0.0570 atm$